Integrand size = 26, antiderivative size = 167 \[ \int x^7 \left (a^2+2 a b x^3+b^2 x^6\right )^{3/2} \, dx=\frac {a^3 x^8 \sqrt {a^2+2 a b x^3+b^2 x^6}}{8 \left (a+b x^3\right )}+\frac {3 a^2 b x^{11} \sqrt {a^2+2 a b x^3+b^2 x^6}}{11 \left (a+b x^3\right )}+\frac {3 a b^2 x^{14} \sqrt {a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )}+\frac {b^3 x^{17} \sqrt {a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )} \]
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Time = 0.03 (sec) , antiderivative size = 167, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.077, Rules used = {1369, 276} \[ \int x^7 \left (a^2+2 a b x^3+b^2 x^6\right )^{3/2} \, dx=\frac {3 a b^2 x^{14} \sqrt {a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )}+\frac {3 a^2 b x^{11} \sqrt {a^2+2 a b x^3+b^2 x^6}}{11 \left (a+b x^3\right )}+\frac {b^3 x^{17} \sqrt {a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )}+\frac {a^3 x^8 \sqrt {a^2+2 a b x^3+b^2 x^6}}{8 \left (a+b x^3\right )} \]
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Rule 276
Rule 1369
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \int x^7 \left (a b+b^2 x^3\right )^3 \, dx}{b^2 \left (a b+b^2 x^3\right )} \\ & = \frac {\sqrt {a^2+2 a b x^3+b^2 x^6} \int \left (a^3 b^3 x^7+3 a^2 b^4 x^{10}+3 a b^5 x^{13}+b^6 x^{16}\right ) \, dx}{b^2 \left (a b+b^2 x^3\right )} \\ & = \frac {a^3 x^8 \sqrt {a^2+2 a b x^3+b^2 x^6}}{8 \left (a+b x^3\right )}+\frac {3 a^2 b x^{11} \sqrt {a^2+2 a b x^3+b^2 x^6}}{11 \left (a+b x^3\right )}+\frac {3 a b^2 x^{14} \sqrt {a^2+2 a b x^3+b^2 x^6}}{14 \left (a+b x^3\right )}+\frac {b^3 x^{17} \sqrt {a^2+2 a b x^3+b^2 x^6}}{17 \left (a+b x^3\right )} \\ \end{align*}
Time = 1.02 (sec) , antiderivative size = 61, normalized size of antiderivative = 0.37 \[ \int x^7 \left (a^2+2 a b x^3+b^2 x^6\right )^{3/2} \, dx=\frac {x^8 \sqrt {\left (a+b x^3\right )^2} \left (1309 a^3+2856 a^2 b x^3+2244 a b^2 x^6+616 b^3 x^9\right )}{10472 \left (a+b x^3\right )} \]
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Time = 6.20 (sec) , antiderivative size = 58, normalized size of antiderivative = 0.35
method | result | size |
gosper | \(\frac {x^{8} \left (616 b^{3} x^{9}+2244 b^{2} x^{6} a +2856 a^{2} b \,x^{3}+1309 a^{3}\right ) {\left (\left (b \,x^{3}+a \right )^{2}\right )}^{\frac {3}{2}}}{10472 \left (b \,x^{3}+a \right )^{3}}\) | \(58\) |
default | \(\frac {x^{8} \left (616 b^{3} x^{9}+2244 b^{2} x^{6} a +2856 a^{2} b \,x^{3}+1309 a^{3}\right ) {\left (\left (b \,x^{3}+a \right )^{2}\right )}^{\frac {3}{2}}}{10472 \left (b \,x^{3}+a \right )^{3}}\) | \(58\) |
risch | \(\frac {a^{3} x^{8} \sqrt {\left (b \,x^{3}+a \right )^{2}}}{8 b \,x^{3}+8 a}+\frac {3 a^{2} b \,x^{11} \sqrt {\left (b \,x^{3}+a \right )^{2}}}{11 \left (b \,x^{3}+a \right )}+\frac {3 a \,b^{2} x^{14} \sqrt {\left (b \,x^{3}+a \right )^{2}}}{14 \left (b \,x^{3}+a \right )}+\frac {b^{3} x^{17} \sqrt {\left (b \,x^{3}+a \right )^{2}}}{17 b \,x^{3}+17 a}\) | \(116\) |
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Time = 0.26 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.21 \[ \int x^7 \left (a^2+2 a b x^3+b^2 x^6\right )^{3/2} \, dx=\frac {1}{17} \, b^{3} x^{17} + \frac {3}{14} \, a b^{2} x^{14} + \frac {3}{11} \, a^{2} b x^{11} + \frac {1}{8} \, a^{3} x^{8} \]
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\[ \int x^7 \left (a^2+2 a b x^3+b^2 x^6\right )^{3/2} \, dx=\int x^{7} \left (\left (a + b x^{3}\right )^{2}\right )^{\frac {3}{2}}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.21 \[ \int x^7 \left (a^2+2 a b x^3+b^2 x^6\right )^{3/2} \, dx=\frac {1}{17} \, b^{3} x^{17} + \frac {3}{14} \, a b^{2} x^{14} + \frac {3}{11} \, a^{2} b x^{11} + \frac {1}{8} \, a^{3} x^{8} \]
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Time = 0.29 (sec) , antiderivative size = 67, normalized size of antiderivative = 0.40 \[ \int x^7 \left (a^2+2 a b x^3+b^2 x^6\right )^{3/2} \, dx=\frac {1}{17} \, b^{3} x^{17} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {3}{14} \, a b^{2} x^{14} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {3}{11} \, a^{2} b x^{11} \mathrm {sgn}\left (b x^{3} + a\right ) + \frac {1}{8} \, a^{3} x^{8} \mathrm {sgn}\left (b x^{3} + a\right ) \]
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Timed out. \[ \int x^7 \left (a^2+2 a b x^3+b^2 x^6\right )^{3/2} \, dx=\int x^7\,{\left (a^2+2\,a\,b\,x^3+b^2\,x^6\right )}^{3/2} \,d x \]
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